+ nDj v^RIt^RIt^RIHtHtHtHtHtHt^RI H t ^RI H t R.t ] !RR7R Rl4tR#) N)zerosasarrayeyepoly1dhstackr_)linalg)xp_capabilitiespadeT) out_of_scopec\PP\43pRp\P !V\ VR7\V4pVf,\V4^, V, pV^8d \R4hV^8d \R4hW,pV\V4^, 8d \R4hVRV^,p\V^,V^,VPR7p\V^,V3VPR7p\^V^,4FpVRVRRR 1,)WxRV13&K \V^,V^,4FpWV, VRRR 1,)WxR3&K \Wg34p \P !W4p V RV^,p \"R W^,R3,p \%V RRR 1,4\%V RRR 1,43#) a Return Pade approximation to a polynomial as the ratio of two polynomials. .. deprecated:: 1.18.0 This function is deprecated and will be removed in SciPy 1.20.0. Use `mpmath.pade` instead. Parameters ---------- an : (N,) array_like Taylor series coefficients. m : int The order of the returned approximating polynomial `q`. n : int, optional The order of the returned approximating polynomial `p`. By default, the order is ``len(an)-1-m``. Returns ------- p, q : Polynomial class The Pade approximation of the polynomial defined by `an` is ``p(x)/q(x)``. Examples -------- >>> import numpy as np >>> from scipy.interpolate import pade >>> e_exp = [1.0, 1.0, 1.0/2.0, 1.0/6.0, 1.0/24.0, 1.0/120.0] >>> p, q = pade(e_exp, 2) >>> e_exp.reverse() >>> e_poly = np.poly1d(e_exp) Compare ``e_poly(x)`` and the Pade approximation ``p(x)/q(x)`` >>> e_poly(1) 2.7166666666666668 >>> p(1)/q(1) 2.7179487179487181 zT`pade` is deprecated and will be removed in SciPy 1.20.0. Use `mpmath.pade` instead.)skip_file_prefixesNz.Order of q must be smaller than len(an)-1.z&Order of p must be greater than 0.z0Order of q+p must be smaller than len(an).)dtype:NNNg?)ospathdirname__file__warningswarnDeprecationWarningrlen ValueErrorrrrrangerr solverr) anmn _warn_skipsmsgNAkjBkjrowCpqpqs &&& Q/data/cameron/venvs/s3viz/lib/python3.14/site-packages/scipy/interpolate/_pade.pyr r sX77??8,.K $C MM#)kJ By GaK!O q5MN N1uABB A3r719}KLL DQqSB ac1Q3bhh 'C 1a )CQ!}Tc(DbD))H QqS!A#a%}dd++E zA a B 4AaCA 3Q34=A !DbD'?F1TrT7O ++)N)rrnumpyrrrrrrscipyr scipy._lib._array_apir __all__r r*r)r0s7 991 (d#D,$D,r*